On Sun, 20 Mar 2011 15:04:27 +0100, Jason Mulligan
<[email protected]> wrote:
return ((arg % 2) === 0) ? true : false;
Just on general principle, the "? true : false" part is completely
unnecessary. The condition
is already a boolean, so just do:
return ((arg % 2) === 0);
If arg is a non-integer number, this will return false. I assume arg
should be an integer.
You can force that by instead doing:
return ((arg & 1) === 0);
That converts arg1 to a 32-bit integer by truncation, and then tests
whether bit 0 is clear.
I.e., 12.3 is even, 13.5 is odd.
If you are into brevity (which there isn't really a good reason for), you
can even do
return !(arg & 1);
/L
--
Lasse Reichstein Holst Nielsen - [email protected]
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