Sorry, that is a compiler error, not a logic error (as is the misspelling of
tmpString elsewhere in the program). It will not cause the error reported.
----- Original Message -----
From: Peter Zhou <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, December 20, 2000 5:47 PM
Subject: Re: arrays
> Sorry! my first reply to your is wrong, and you have no indexing problem
.
> But your have code "String array2 = new String[j];", that is wrong.
> it should be "String[] array2 = new String[j];". I hope this is the fix
to your
> problem, and save my own wrong answer before.
>
> Shirley Chen wrote:
>
> > Thanks for replying. But my boss insists that I use array because
vector
> > costs more memory and time.
> >
> > >From: Shawn Zhu <[EMAIL PROTECTED]>
> > >Reply-To: A mailing list about Java Server Pages specification and
> > > reference <[EMAIL PROTECTED]>
> > >To: [EMAIL PROTECTED]
> > >Subject: Re: arrays
> > >Date: Wed, 20 Dec 2000 13:06:06 -0800
> > >
> > >Why don't you just use Vector?
> > >--------
> > >Vector v_queryResult = New Vector();
> > >...
> > >if(tmpString.indexOf('C')!=-1)
> > >{
> > > v_queryResult.addElement((Object)tmpString);
> > >}
> > >--------
> > >Then there's no need for Array2.
> > >
> > >
> > > > -----Original Message-----
> > > > From: Shirley Chen [mailto:[EMAIL PROTECTED]]
> > > > Sent: Wednesday, December 20, 2000 11:39 AM
> > > > To: [EMAIL PROTECTED]
> > > > Subject: arrays
> > > >
> > > >
> > > > Hi,
> > > >
> > > > I have a question, somebody please help me:
> > > >
> > > > I have a vector which will keep all the names the user typed
> > > > in. Then the
> > > > user supposes can do a query like "give me all the name which
> > > > starts with
> > > > 'C'". In order to do that, I do something like this:
> > > >
> > > > ...
> > > > String[] array1 = new String[myVector.size()];
> > > > String tempString = "";
> > > > int j=0;
> > > >
> > > > for (int i=0; i<myVector.size(); i++)
> > > > {
> > > > tmpString = (String)myVector.get(i);
> > > > if (tmpString.indexOf('C') != -1)
> > > > {
> > > > array1[j] = tmpString;
> > > > j++;
> > > > }
> > > > }
> > > >
> > > > file://since array1 may not be filled up with data, I transfer it
> > > > to another
> > > > String array so I know how many element in the array
> > > >
> > > > String array2 = new String[j];
> > > > for (int i=0; i<j; i++)
> > > > {
> > > > array2[i] = array1[i];
> > > > }
> > > >
> > > > // then I will do display. Supposedly, say, array2.length is
> > > > 20, if the user
> > > > wants to display first 5, I will display only the first 5
> > > > records, if the
> > > > user wants to display 30, and I will display 20 instead.
> > > > ...
> > > >
> > > > I can display all the situations ok except when myVector
> > > > contains the names
> > > > that all start with "C" (which means array2.length should be
> > > > myVector.size()). then the program will crash. I think it
> > > > might be array
> > > > out of bound problem, but I don't know how to fix it. Please help
me.
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