Thanks Ivan for the informative pages..
Cheers,
Venu
--- Ivan Kougaenko <[EMAIL PROTECTED]> wrote:
> there's a good article
>
(http://www.javaworld.com/jw-12-1999/jw-12-performance.html)
> on vectors,
> casting, and performance.
>
> -----Original Message-----
> From: A mailing list about Java Server Pages
> specification and reference
> [mailto:[EMAIL PROTECTED]]On Behalf Of Venu
> Gopal
> Sent: Saturday, December 23, 2000 10:07 PM
> To: [EMAIL PROTECTED]
> Subject: Re: arrays
>
>
> But then Geert.. which one is the faster .. Arrays
> or
> Vectors.. and why?
>
> Thanks in advance,
>
> Venu
>
> --- Geert Van Damme <[EMAIL PROTECTED]>
> wrote:
> > If that's true, your boss is stupid.
> >
> > Java costs memory and time too, why don't you use
> > assembler?
> > Most probably, the time it took you (and the $) is
> > much higher than the
> > aggregated difference between sing a vector and an
> > array will ever be.
> > That's why this is absolutely stupid!
> >
> > If I program 1 hour to gain a millisecond, it
> takes
> > 3.600.000 runs of the
> > function before there's any gain.
> > 1 hour is nothing.
> > 3.600.000 is a lot ;-)
> >
> >
> > Geert Van Damme
> >
> >
> > > -----Original Message-----
> > > From: A mailing list about Java Server Pages
> > specification and reference
> > > [mailto:[EMAIL PROTECTED]]On Behalf Of
> > Shirley Chen
> > > Sent: woensdag 20 december 2000 22:11
> > > To: [EMAIL PROTECTED]
> > > Subject: Re: arrays
> > >
> > >
> > > Thanks for replying. But my boss insists that I
> > use array because vector
> > > costs more memory and time.
> > >
> > >
> > >
> > > >From: Shawn Zhu <[EMAIL PROTECTED]>
> > > >Reply-To: A mailing list about Java Server
> Pages
> > specification and
> > > > reference <[EMAIL PROTECTED]>
> > > >To: [EMAIL PROTECTED]
> > > >Subject: Re: arrays
> > > >Date: Wed, 20 Dec 2000 13:06:06 -0800
> > > >
> > > >Why don't you just use Vector?
> > > >--------
> > > >Vector v_queryResult = New Vector();
> > > >...
> > > >if(tmpString.indexOf('C')!=-1)
> > > >{
> > > >
> > v_queryResult.addElement((Object)tmpString);
> > > >}
> > > >--------
> > > >Then there's no need for Array2.
> > > >
> > > >
> > > > > -----Original Message-----
> > > > > From: Shirley Chen
> > [mailto:[EMAIL PROTECTED]]
> > > > > Sent: Wednesday, December 20, 2000 11:39 AM
> > > > > To: [EMAIL PROTECTED]
> > > > > Subject: arrays
> > > > >
> > > > >
> > > > > Hi,
> > > > >
> > > > > I have a question, somebody please help me:
> > > > >
> > > > > I have a vector which will keep all the
> names
> > the user typed
> > > > > in. Then the
> > > > > user supposes can do a query like "give me
> all
> > the name which
> > > > > starts with
> > > > > 'C'". In order to do that, I do something
> > like this:
> > > > >
> > > > > ...
> > > > > String[] array1 = new
> String[myVector.size()];
> > > > > String tempString = "";
> > > > > int j=0;
> > > > >
> > > > > for (int i=0; i<myVector.size(); i++)
> > > > > {
> > > > > tmpString = (String)myVector.get(i);
> > > > > if (tmpString.indexOf('C') != -1)
> > > > > {
> > > > > array1[j] = tmpString;
> > > > > j++;
> > > > > }
> > > > > }
> > > > >
> > > > > //since array1 may not be filled up with
> data,
> > I transfer it
> > > > > to another
> > > > > String array so I know how many element in
> the
> > array
> > > > >
> > > > > String array2 = new String[j];
> > > > > for (int i=0; i<j; i++)
> > > > > {
> > > > > array2[i] = array1[i];
> > > > > }
> > > > >
> > > > > // then I will do display. Supposedly, say,
> > array2.length is
> > > > > 20, if the user
> > > > > wants to display first 5, I will display
> only
> > the first 5
> > > > > records, if the
> > > > > user wants to display 30, and I will display
> > 20 instead.
> > > > > ...
> > > > >
> > > > > I can display all the situations ok except
> > when myVector
> > > > > contains the names
> > > > > that all start with "C" (which means
> > array2.length should be
> > > > > myVector.size()). then the program will
> crash.
> > I think it
> > > > > might be array
> > > > > out of bound problem, but I don't know how
> to
> > fix it. Please help me.
> > > > >
> >
>
_________________________________________________________________
> > > > > Get your FREE download of MSN Explorer at
> > http://explorer.msn.com
> > > > >
> > > > >
> >
>
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