This runs fine for me, running Version 0.3.0-prerelease (2014-02-28 04:44
UTC):
f(i,j) = [i,j]
n=3; m=2
a = [f(i, j) for i in 1:n, j in 1:m]
Out[91]:
3x2 Array{Any,2}:
[1,1] [1,2]
[2,1] [2,2]
[3,1] [3,2]
On Monday, March 24, 2014 10:07:49 AM UTC-4, Linus Mellberg wrote:
>
> Hi!
>
> I'm trying to construct a 3 dimensional array from a number of 1
> dimensional arrays. Essentially what i would like to do is
>
> a = [f(i, j) for i in 1:n, j in 1:m]
>
> where f(i, j) is a function that returns an array (note, f has to
> construct the entire array at the same time). The code above creates a
> 2-dimensional array of arrays, but I would like to get a 3-dimensional
> array with the arrays returned by f in the first dimension with i and j in
> the second and third dimension, hope you understand
>
> a[:,:,1] = [f(1,1) f(2,1) ... f(n,1)]
> a[:,:,2] = [f(1,2) f(2,2) ... f(n,2)]
> .
> .
> .
> a[:,:,m] = [f(1,m) f(2,m) ... f(n,m)]
>
> f(i,j) are column arrays above.
>
> It can be achieved by first creating the large matrix and then filling it
>
> a = zeros(Int64, k, n, m)
> for i in 1:n, j in 1:m
> a[:,i,j] = f(i,j)
> end
>
> Is this the only way? I find it sort of ugly when its usually possible to
> do nice construction using comprehensions in other cases.
>
>
