Hi, I guess you want a 3d array instead of a 2D array containing 1D arrays. I tried this:
arrayLength = 10; matrixCols = 10; matrixSlices= 10; function arrayTest(arrayLength,i,j) singleArray = ones(1,arrayLength)*(i+j); #each array has a unique value i+jreturn singleArrayend matrix3d = [arrayTest(arrayLength,i,j)[k] for k=1:arrayLength, i=1:matrixCols, j=1:matrixSlices ]; matrix3d[:,1,1] It works fine ;) Le lundi 24 mars 2014 15:07:49 UTC+1, Linus Mellberg a écrit : > > Hi! > > I'm trying to construct a 3 dimensional array from a number of 1 > dimensional arrays. Essentially what i would like to do is > > a = [f(i, j) for i in 1:n, j in 1:m] > > where f(i, j) is a function that returns an array (note, f has to > construct the entire array at the same time). The code above creates a > 2-dimensional array of arrays, but I would like to get a 3-dimensional > array with the arrays returned by f in the first dimension with i and j in > the second and third dimension, hope you understand > > a[:,:,1] = [f(1,1) f(2,1) ... f(n,1)] > a[:,:,2] = [f(1,2) f(2,2) ... f(n,2)] > . > . > . > a[:,:,m] = [f(1,m) f(2,m) ... f(n,m)] > > f(i,j) are column arrays above. > > It can be achieved by first creating the large matrix and then filling it > > a = zeros(Int64, k, n, m) > for i in 1:n, j in 1:m > a[:,i,j] = f(i,j) > end > > Is this the only way? I find it sort of ugly when its usually possible to > do nice construction using comprehensions in other cases. > >
