Hi, I guess you want a 3d array instead of a 2D array containing 1D arrays. 
I tried this:

arrayLength = 10;

matrixCols  = 10;

matrixSlices= 10;
function arrayTest(arrayLength,i,j)        singleArray = 
ones(1,arrayLength)*(i+j); #each array has a unique value i+jreturn 
singleArrayend

matrix3d = [arrayTest(arrayLength,i,j)[k] for k=1:arrayLength, i=1:matrixCols, 
j=1:matrixSlices ];
matrix3d[:,1,1] 

It works fine ;)



Le lundi 24 mars 2014 15:07:49 UTC+1, Linus Mellberg a écrit :
>
> Hi!
>
> I'm trying to construct a 3 dimensional array from a number of 1 
> dimensional arrays. Essentially what i would like to do is
>
> a = [f(i, j) for i in 1:n, j in 1:m]
>
> where f(i, j) is a function that returns an array (note, f has to 
> construct the entire array at the same time). The code above creates a 
> 2-dimensional array of arrays, but I would like to get a 3-dimensional 
> array with the arrays returned by f in the first dimension with i and j in 
> the second and third dimension, hope you understand
>
> a[:,:,1] = [f(1,1) f(2,1) ... f(n,1)]
> a[:,:,2] = [f(1,2) f(2,2) ... f(n,2)]
> .
> .
> .
> a[:,:,m] = [f(1,m) f(2,m) ... f(n,m)]
>
> f(i,j) are column arrays above.
>
> It can be achieved by first creating the large matrix and then filling it
>
> a = zeros(Int64, k, n, m)
> for i in 1:n, j in 1:m
>   a[:,i,j] = f(i,j)
> end
>
> Is this the only way? I find it sort of ugly when its usually possible to 
> do nice construction using comprehensions in other cases.
>
>

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