Thanks for the one-line expression. Hence, if I want to assign this new function to the existing variable "f" using one line, I can do
f = f1(a,b) = f2(3, a, b) It will work for me! Joan El miércoles, 4 de junio de 2014 11:39:40 UTC+1, Tomas Lycken escribió: > > I don't think you can avoid f1 completely, but there is a one-line syntax > to obtain the same thing: > > f1(a,b) = f2(3,a,b) > > I can't imagine a syntax to express that thing that is more compact yet > equally expressive. > > // T > > On Wednesday, June 4, 2014 12:37:47 PM UTC+2, joanenric barcelo wrote: >> >> First of all, sorry if the question in the title is not well explained. >> Basically, what I want to know if some of you guys know a nicer way to do >> the following: >> >> function f2(a, b, c) >> return a+b+c >> end >> >> f = function f1(a,b) >> f2(3,a,b) >> end >> so >> f(1,1) >> is 5 >> >> What I want to do is to create a new function "f" which is similar to >> "f2" but with only two arguments. The first argument is implicit. >> Anyone knows how f1 can be avoided? Thanks!! >> >> Joan >> >
