Thanks! In addition to Tomas answer, I can do f = (a,b) -> f2(3, a, b)
Since both options work for me, which one do you guys think is more legible? Joan El miércoles, 4 de junio de 2014 11:51:46 UTC+1, Mauro escribió: > > You can also make an anonymous function and assign it to a variable: > ff = (x,y) -> f2(3,x,y) > > But Thomas' suggestion is nicer: > > f(a,b) = f2(3,a,b) > > The anonymous function approach is shorter if you need to pass it to a > function, e.g.: > map(x -> f2(3,4,x), 1:5) > > But I think they have not the same performance as proper functions. > > On Wed, 2014-06-04 at 11:39, tomas....@gmail.com <javascript:> wrote: > > I don't think you can avoid f1 completely, but there is a one-line > syntax > > to obtain the same thing: > > > > f1(a,b) = f2(3,a,b) > > > > I can't imagine a syntax to express that thing that is more compact yet > > equally expressive. > > > > // T > > > > On Wednesday, June 4, 2014 12:37:47 PM UTC+2, joanenric barcelo wrote: > >> > >> First of all, sorry if the question in the title is not well explained. > >> Basically, what I want to know if some of you guys know a nicer way to > do > >> the following: > >> > >> function f2(a, b, c) > >> return a+b+c > >> end > >> > >> f = function f1(a,b) > >> f2(3,a,b) > >> end > >> so > >> f(1,1) > >> is 5 > >> > >> What I want to do is to create a new function "f" which is similar to > "f2" > >> but with only two arguments. The first argument is implicit. > >> Anyone knows how f1 can be avoided? Thanks!! > >> > >> Joan > >> > >
