Sorry I left out the function call:
for i=1:100
eval(parse("m$i = readcsv(\"m$i.txt\")"))
end
On Wed, Jun 4, 2014 at 11:16 AM, Bob Nnamtrop <[email protected]>
wrote:
> Or closer to the syntax of the original loop:
>
> for i=1:100
> eval(parse("m$i = \"m$i.txt\""))
> end
>
> Bob
>
>
>
> On Wed, Jun 4, 2014 at 11:13 AM, Patrick O'Leary <[email protected]
> > wrote:
>
>> First, you probably would be better off with an array, rather than 100
>> variables with numeric postfixes. You can use push!() for this.
>>
>> Second, the error is because Julia is trying to parse the left hand side
>> as an attempt to define a function, using the shortened f(x) = y function
>> definition syntax. Here, f is *, and the literal `"m" * string(i)` is being
>> interpreted as the name of its argument, but this is not a valid identifier.
>>
>> Finally, although you almost certainly don't want to do what you're
>> trying to do, you can if you separate creation of the symbol from
>> evaluation:
>>
>> var_name = symbol("m" * string(i))
>> @eval $var_name = readcsv(string("m", i, ".txt"))
>>
>>
>> On Wednesday, June 4, 2014 11:36:37 AM UTC-5, paul analyst wrote:
>>>
>>> dynamic creation and naming of variables, what wrong?
>>>
>>> I need 100 new variables : m1 to m 100
>>>
>>> julia> for i=1:100
>>> "m" * string(i)=readcsv(string("m",i,".txt"))
>>> end
>>> ERROR: syntax: "#<julia_value>" is not a valid function argument name
>>>
>>
>
