Big txh, it works,
but now i heve 100 arrays (in real more... ) with 99 empty columns. Is
posible read m1 , m2 to vector , not to array ?
Paul
W dniu środa, 4 czerwca 2014 19:22:11 UTC+2 użytkownik Bob Nnamtrop napisał:
>
> Sorry I left out the function call:
>
> for i=1:100
> eval(parse("m$i = readcsv(\"m$i.txt\")"))
> end
>
>
>
> On Wed, Jun 4, 2014 at 11:16 AM, Bob Nnamtrop <[email protected]
> <javascript:>> wrote:
>
>> Or closer to the syntax of the original loop:
>>
>> for i=1:100
>> eval(parse("m$i = \"m$i.txt\""))
>> end
>>
>> Bob
>>
>>
>>
>> On Wed, Jun 4, 2014 at 11:13 AM, Patrick O'Leary <[email protected]
>> <javascript:>> wrote:
>>
>>> First, you probably would be better off with an array, rather than 100
>>> variables with numeric postfixes. You can use push!() for this.
>>>
>>> Second, the error is because Julia is trying to parse the left hand side
>>> as an attempt to define a function, using the shortened f(x) = y function
>>> definition syntax. Here, f is *, and the literal `"m" * string(i)` is being
>>> interpreted as the name of its argument, but this is not a valid identifier.
>>>
>>> Finally, although you almost certainly don't want to do what you're
>>> trying to do, you can if you separate creation of the symbol from
>>> evaluation:
>>>
>>> var_name = symbol("m" * string(i))
>>> @eval $var_name = readcsv(string("m", i, ".txt"))
>>>
>>>
>>> On Wednesday, June 4, 2014 11:36:37 AM UTC-5, paul analyst wrote:
>>>>
>>>> dynamic creation and naming of variables, what wrong?
>>>>
>>>> I need 100 new variables : m1 to m 100
>>>>
>>>> julia> for i=1:100
>>>> "m" * string(i)=readcsv(string("m",i,".txt"))
>>>> end
>>>> ERROR: syntax: "#<julia_value>" is not a valid function argument name
>>>>
>>>
>>
>
