That seems likely.
> On Aug 18, 2014, at 7:24 PM, Elliot Saba <[email protected]> wrote: > > Probably because of our special parsing of & in ccall invocations. > -E > > >> On Mon, Aug 18, 2014 at 7:14 PM, Stefan Karpinski <[email protected]> >> wrote: >> Yeah, I forget exactly why you can't to that with & but there's some parsing >> ambiguity. >> >> >>> On Mon, Aug 18, 2014 at 6:33 PM, ggggg <[email protected]> wrote: >>> Ok, thanks. Although it doesn't seem to be the case for |, eg "|(true, >>> false)" works out of the box. >>> >>> >>>> On Monday, August 18, 2014 4:24:31 PM UTC-6, Stefan Karpinski wrote: >>>> This are some of those few operators that need parens to be used in >>>> function call syntax: >>>> >>>> julia> (&)(3,5) >>>> 1 >>>> >>>> julia> (|)(3,5) >>>> 7 >>>> >>>> This isn't required in unambiguous situations like as an argument to >>>> another function: >>>> >>>> julia> reduce(|, 0:8) >>>> 15 >>>> >>>> >>>> >>>>> On Mon, Aug 18, 2014 at 6:20 PM, ggggg <[email protected]> wrote: >>>>> Is there a named function that does what & does, eg "&(a,b) == a&b"? I >>>>> actually want a multi argument version like "$(a,b,c...)". Also is that >>>>> the name of that function is not "&" and "& is not overloadable? The same >>>>> is not true of "|". >>>>> >>>>> julia> a = zeros(Bool,10);b=[randbool() for j=1:10]; >>>>> >>>>> julia> a&b==b >>>>> >>>>> false >>>>> >>>>> julia> a|b==b >>>>> >>>>> true >>>>> >>>>> julia> |(a,b)==b >>>>> >>>>> true >>>>> >>>>> julia> &(a,b)==b >>>>> >>>>> ERROR: unsupported or misplaced expression & >>>>> >>>>> julia> &(a,b) = a&b >>>>> >>>>> ERROR: syntax: invalid assignment location >>>>> >>>>> >>>>> Julia even seems to think & is a function >>>>> julia> & >>>>> >>>>> & (generic function with 35 methods) >>>>> >
