This seems like a general programming problem rather than a Julia question.
On Thu, Sep 18, 2014 at 3:36 PM, Paul Analyst <[email protected]> wrote: > No idea ? > > W dniu 2014-09-18 o 13:26, paul analyst pisze: > > I have a vector x = int (randbool (100)) >> a / how quickly (without the loop?) receive 10 vectors of length 10, in >> each field the average of the next 10 fields of the vector x (moving/stepen >> average of 10 values at step = 10)? >> b / how to receive the 99 vectors of length 10 of the next 10 fields >> wektra x (moving/stepen average of 10 values at step = 1)? >> >> Paul >> > >
