This seems to work for me:
*Dates.DateTime("Tue Oct 28 23:24:15.919 2014","e u d HH:MM:SS.sss y")*
I had to add a "d" to capture the day of the month, and lowercased E since
you have abbreviated day of week.
Regards Ivar
kl. 21:28:27 UTC+1 lørdag 1. november 2014 skrev Arshak Navruzyan følgende:
>
> Really basic question about dateformat. I have a date that looks like
> this:
>
> Tue Oct 28 23:24:15.919 2014
>
> Is this the right way to convert to an actual DateTime ?
>
> Dates.DateTime(df[:fulldate],Dates.DateFormat("[E u HH:MM:SS.sss y]"))
>
> Gives me this error currently:
>
> extra characters after whitespace in "28 23"
> while loading In[57], in expression starting on line 2
>
> in error at error.jl:21
> in parseint_nocheck at
> /Applications/Julia-0.3.2.app/Contents/Resources/julia/lib/julia/sys.dylib
> (repeats 2 times)
> in Hour at /Users/arshakn/.julia/v0.3/Dates/src/dates/periods.jl:17
> in getslot at /Users/arshakn/.julia/v0.3/Dates/src/dates/io.jl:108
> in parse at /Users/arshakn/.julia/v0.3/Dates/src/dates/io.jl:120
> in DateTime at /Users/arshakn/.julia/v0.3/Dates/src/dates/io.jl:172
>
>
