Ivar, That worked. Thank you!
Arshak On Sat, Nov 1, 2014 at 2:27 PM, Ivar Nesje <[email protected]> wrote: > This seems to work for me: > > *Dates.DateTime("Tue Oct 28 23:24:15.919 2014","e u d HH:MM:SS.sss y")* > I had to add a "d" to capture the day of the month, and lowercased E since > you have abbreviated day of week. > > Regards Ivar > > kl. 21:28:27 UTC+1 lørdag 1. november 2014 skrev Arshak Navruzyan følgende: > >> Really basic question about dateformat. I have a date that looks like >> this: >> >> Tue Oct 28 23:24:15.919 2014 >> >> Is this the right way to convert to an actual DateTime ? >> >> Dates.DateTime(df[:fulldate],Dates.DateFormat("[E u HH:MM:SS.sss y]")) >> >> Gives me this error currently: >> >> extra characters after whitespace in "28 23" >> while loading In[57], in expression starting on line 2 >> >> in error at error.jl:21 >> in parseint_nocheck at >> /Applications/Julia-0.3.2.app/Contents/Resources/julia/lib/julia/sys.dylib >> (repeats 2 times) >> in Hour at /Users/arshakn/.julia/v0.3/Dates/src/dates/periods.jl:17 >> in getslot at /Users/arshakn/.julia/v0.3/Dates/src/dates/io.jl:108 >> in parse at /Users/arshakn/.julia/v0.3/Dates/src/dates/io.jl:120 >> in DateTime at /Users/arshakn/.julia/v0.3/Dates/src/dates/io.jl:172 >> >>
