I just wanted to double-check that I understand it correctly: doing a vectorized operation to a passed variable inside a function will not change the variable on the outside? Does one have to resort to a `for` loop, or is there another way?
function foo!(x)
x += 10
end
function bar!(x)
[ x[i] += 10 for i in 1:size(x,1) ]
end
y = [1:3]
foo!(y)
println(y)
bar!(y)
println(y)
Output:
[1,2,3]
[1,2,3]
[11,12,13]
Thanks.
