Le lundi 19 janvier 2015 à 21:34 -0800, AVF a écrit :
> I just wanted to double-check that I understand it correctly: doing a
> vectorized operation to a passed variable inside a function will not
> change the variable on the outside?
More or less. `x += 10` is just syntactic sugar for `x = x + 10`: it
allocates a new array, and binds it to x. The original x is not mutated.
> Does one have to resort to a `for` loop, or is there another way?
You can do something like this:
function foo!(x)
x[:] += 10
end
Regards
> function foo!(x)
> x += 10
> end
>
> function bar!(x)
> [ x[i] += 10 for i in 1:size(x,1) ]
> end
>
> y = [1:3]
>
> foo!(y)
> println(y)
>
> bar!(y)
> println(y)
>
>
> Output:
>
>
> [1,2,3]
> [1,2,3]
> [11,12,13]
>
>
> Thanks.
