Wouldn't the answer depend on the path you choose? On Wed, Feb 4, 2015 at 3:04 PM, Andrei Berceanu <[email protected]> wrote:
> I guess what I'm trying to say is that your answer makes sense for > continuous functions, while mine has jumps of 2\pi, and so the phase change > is equal to the total number of these jumps (times 2\pi). Does this make > sense? > > > On Wednesday, February 4, 2015 at 11:36:51 AM UTC+1, Andrei Berceanu wrote: >> >> Sorry, perhaps I did not explain myself :) >> One can see the phase oscillates between -\pi and \pi. >> I would like to compute how many times the phase changes by 2\pi as one >> goes around the origin. >> >> On Wednesday, February 4, 2015 at 1:31:53 AM UTC+1, Steven G. Johnson >> wrote: >>> >>> >>> >>> On Tuesday, February 3, 2015 at 1:17:15 PM UTC-5, Andrei Berceanu wrote: >>> >>>> How can I numerically compute the total change in phase as one goes >>>> around a closed loop centered on the site $m=n=0$? >>>> >>> >>> Seems like >>> >>> totalchangeinphase(m,n) = 0 >>> >>> would work and be very efficient. (As you described your problem, your >>> phase sounds like a single-valued function of m & n, hence the total change >>> around any closed loop would be zero. Unless you mean something different >>> by "total change"?) >>> >>
