It's working fine for me:
julia> x1 = rand(1:10,5); x2 = copy(x1)
5-element Array{Int64,1}:
7
4
6
8
2
julia> errs = [2,4];
julia> deleteat!(x1,errs);
julia> x1
3-element Array{Int64,1}:
7
6
2
julia> for i=length(errs):-1:1
splice!(x2,errs[i])
end
julia> x2
3-element Array{Int64,1}:
7
6
2
On Monday, February 23, 2015 at 8:07:43 AM UTC-5, Aero_flux wrote:
>
> Thanks for the reply. I did try deleteat! without much success. What did
> work for me was the following though:
>
> errors=reverse(errors) #start with the largest index first and work down
>
> for x=1:length(errors)
> splice!(data,errors[x])
> end
>
>
>
> On Monday, February 23, 2015 at 8:17:29 AM UTC, Josh Langsfeld wrote:
>>
>> corrected_data = deleteat!(x, errors) should be what you're looking for.
>> Alternately, a more functionally pure way to do it is to compute the good
>> indices and then just do corrected_data = x[good_idx], though this will
>> make a copy of those elements of x.
>>
>> On Sunday, February 22, 2015 at 3:14:11 PM UTC-5, Aero_flux wrote:
>>>
>>> Hello everybody,
>>>
>>> I might be going about this the wrong way. I have a sequence of data in
>>> a 1-D array "x". Now I have done some calculations and have a 1-D array of
>>> the indexed points in "x" that erroneous. What I would like to to is remove
>>> all the data points in "x" that uses the saved indices. I figured I would
>>> use corrected_data = splice!(x, errors) but of course it won't take arrays.
>>> Any hints?
>>>
>>> Many thanks
>>>
>>
