Yup you are absolutely right. Working for me as well. Thought I would give
the @time macro a try. Haven't used it before. Will stick to deleteat!.
Thanks
function f1(n)
x1 = rand(1:10,5);
errs = [2,4];
deleteat!(x1,errs);
end
function f2(n)
x1 = rand(1:10,5);
errs = [2,4];
for i=length(errs):-1:1
splice!(x2,errs[i])
end
end
julia> @time f1(1)
elapsed time: 0.266245646 seconds (595924 bytes allocated)
julia> @time f2(1)
elapsed time: 0.59141116 seconds (1087272 bytes allocated)
On Monday, February 23, 2015 at 3:08:08 PM UTC, Josh Langsfeld wrote:
>
> It's working fine for me:
>
> julia> x1 = rand(1:10,5); x2 = copy(x1)
> 5-element Array{Int64,1}:
> 7
> 4
> 6
> 8
> 2
>
> julia> errs = [2,4];
>
> julia> deleteat!(x1,errs);
>
> julia> x1
> 3-element Array{Int64,1}:
> 7
> 6
> 2
>
> julia> for i=length(errs):-1:1
> splice!(x2,errs[i])
> end
>
> julia> x2
> 3-element Array{Int64,1}:
> 7
> 6
> 2
>
>
>
>
> On Monday, February 23, 2015 at 8:07:43 AM UTC-5, Aero_flux wrote:
>>
>> Thanks for the reply. I did try deleteat! without much success. What did
>> work for me was the following though:
>>
>> errors=reverse(errors) #start with the largest index first and work down
>>
>> for x=1:length(errors)
>> splice!(data,errors[x])
>> end
>>
>>
>>
>> On Monday, February 23, 2015 at 8:17:29 AM UTC, Josh Langsfeld wrote:
>>>
>>> corrected_data = deleteat!(x, errors) should be what you're looking for.
>>> Alternately, a more functionally pure way to do it is to compute the good
>>> indices and then just do corrected_data = x[good_idx], though this will
>>> make a copy of those elements of x.
>>>
>>> On Sunday, February 22, 2015 at 3:14:11 PM UTC-5, Aero_flux wrote:
>>>>
>>>> Hello everybody,
>>>>
>>>> I might be going about this the wrong way. I have a sequence of data in
>>>> a 1-D array "x". Now I have done some calculations and have a 1-D array of
>>>> the indexed points in "x" that erroneous. What I would like to to is
>>>> remove
>>>> all the data points in "x" that uses the saved indices. I figured I would
>>>> use corrected_data = splice!(x, errors) but of course it won't take
>>>> arrays.
>>>> Any hints?
>>>>
>>>> Many thanks
>>>>
>>>
