One thing I forgot to ask is .... what if I wan to keep the array as it is and then add to it ...if I run a = filter(x->x<3, z) ... it overwrites the array. Regards
On Wednesday, 18 March 2015 14:04:45 UTC, [email protected] wrote: > > Thanks everybody - got it! > Regards > > On Wednesday, 18 March 2015 12:04:48 UTC, René Donner wrote: >> >> or simply >> >> a = filter(x->x<3, z) >> >> Am Mittwoch, 18. März 2015 12:46:52 UTC+1 schrieb Konstantin Markov: >>> >>> julia> a = [i for i=filter(x->x<3,z)] >>> 2-element Array{Any,1}: >>> 1 >>> 2 >>> >>> >>> On Wednesday, March 18, 2015 at 8:31:57 PM UTC+9, [email protected] >>> wrote: >>>> >>>> Hi >>>> I want to fill an array based on a condition - eg >>>> >>>> a = [] >>>> z = [1,2,3,4] >>>> >>>> for i = 1:length(z) >>>> if i > 2 >>>> continue >>>> end >>>> end >>>> >>>> so, I would now like to see the values 1 & 2 in my array "a" >>>> Regards >>>> >>>> >>>> >>>> >>>>
