julia> z = [1,2,3,4]
...
julia> a = filter(x->x<3, z)
...
julia> c = [a;z]
6-element Array{Int64,1}:
1
2
1
2
3
4
I think you will find most of what you need in
http://docs.julialang.org/en/release-0.3/manual/arrays/
Am 18.03.2015 um 20:55 schrieb pgs <[email protected]>:
> Hi
> I guess what I'm trying to say is that if array "a" started life as
> [11,12,13,14] - then if we use "filter(x->x<3, z)" which returns 1,2 - I
> would like 1,2 added to array a resulting in "a array" being .....
> [11,12,13,14,1,2] or [1,2,11,12,13,14]
> Regards
>
> On Wednesday, March 18, 2015 at 3:05:54 PM UTC, René Donner wrote:
> I am not sure what you mean - are you expecting a different behavior than
> this? Both z and a are containing what they should.
>
> julia> z = [1,2,3,4]
> 4-element Array{Int64,1}:
> 1
> 2
> 3
> 4
>
> julia> a = filter(x->x<3, z)
> 2-element Array{Int64,1}:
> 1
> 2
>
> julia> z
> 4-element Array{Int64,1}:
> 1
> 2
> 3
> 4
>
> julia> a
> 2-element Array{Int64,1}:
> 1
> 2
>
>
> Am Mittwoch, 18. März 2015 16:01:11 UTC+1 schrieb [email protected]:
> One thing I forgot to ask is .... what if I wan to keep the array as it is
> and then add to it ...if I run a = filter(x->x<3, z) ... it overwrites the
> array.
> Regards
>
> On Wednesday, 18 March 2015 14:04:45 UTC, [email protected] wrote:
> Thanks everybody - got it!
> Regards
>
> On Wednesday, 18 March 2015 12:04:48 UTC, René Donner wrote:
> or simply
>
> a = filter(x->x<3, z)
>
> Am Mittwoch, 18. März 2015 12:46:52 UTC+1 schrieb Konstantin Markov:
> julia> a = [i for i=filter(x->x<3,z)]
> 2-element Array{Any,1}:
> 1
> 2
>
>
> On Wednesday, March 18, 2015 at 8:31:57 PM UTC+9, [email protected] wrote:
> Hi
> I want to fill an array based on a condition - eg
>
> a = []
> z = [1,2,3,4]
>
> for i = 1:length(z)
> if i > 2
> continue
> end
> end
>
> so, I would now like to see the values 1 & 2 in my array "a"
> Regards
>
>
>
>
