I was actually arguing in the other direction – if leading type parameters
match, narrow those in the typejoin. That would make
typejoin(Woo{Int,Int},Woo{Int,Float64}) == Woo{Int}. You could also do that
for non-leading type parameters but that seems less obvious somehow. That
would mean that typejoin(Woo{Int,Int},Woo{Float64,Int}) == Woo{*,Int} where
we don't currently have an input syntax for that last type (but we can
create it using a type alias).

On Wed, Apr 1, 2015 at 2:16 PM, Jeff Bezanson <[email protected]>
wrote:

> Yes, arguably typejoin should just walk up the hierarchy and not try
> to do fancier joins. However if there are no parameters in common,
> e.g.
>
> a = Wow{W, X}()
> b = Wow{Y, Z}()
>
> then the result would be Any.
>
> On Wed, Apr 1, 2015 at 11:45 AM, Stefan Karpinski <[email protected]>
> wrote:
> > Arguably typejoin should do that.
> >
> > On Wed, Apr 1, 2015 at 11:35 AM, Michael Francis <[email protected]>
> > wrote:
> >>
> >> In this instance I'm happy to have the abstract type as the promoted
> type.
> >> E.g. I would like to see this be Array{Foo{Int64},1} and not
> Array{Foo{K},1}
> >> Can I satisfy this with a promote rule ?
> >>
> >> On Wednesday, April 1, 2015 at 11:29:08 AM UTC-4, Stefan Karpinski
> wrote:
> >>>
> >>> This is computed by the promote_type and typejoin functions defined in
> >>> promotion.jl:
> >>>
> >>> https://github.com/JuliaLang/julia/blob/master/base/promotion.jl
> >>>
> >>>
> >>> promote_type tries to find a single concrete type to convert a
> collection
> >>> of types to. As a fallback, if it can't do that, it calls typejoin on
> the
> >>> types, which walks up the type hierarchy and tries to find a common
> abstract
> >>> supertype of its arguments. Since these types don't have any
> promote_rule
> >>> methods, all examples fall back on typejoin, which exhibits the
> behavior
> >>> you're seeing here:
> >>>
> >>> julia> typejoin(typeof(a))
> >>> Wow{Int64,Int64}
> >>>
> >>> julia> typejoin(typeof(a),typeof(b))
> >>> Wow{K,V}
> >>>
> >>> julia> typejoin(typeof(a),typeof(c))
> >>> Foo{Int64}
> >>>
> >>> julia> typejoin(typeof(a),typeof(b),typeof(c))
> >>> Foo{Int64}
> >>>
> >>> julia> typejoin(typeof(a),typeof(c),typeof(b))
> >>> Foo{Int64}
> >>>
> >>> julia> typejoin(typeof(a),typeof(b),typeof(c),typeof(d))
> >>> Foo{K}
> >>>
> >>>
> >>> One way to hook into this system and get different results is to define
> >>> promote_rule methods to determine what "wins" when you promote
> different Wow
> >>> and Foo types together. For example, you could define this (requires a
> >>> restart dues to #265):
> >>>
> >>> Base.convert{K,V}(::Type{Wow{K,V}}, x::Wow) = Wow{K,V}()
> >>>
> >>> Base.promote_rule{K1,V1,K2,V2}(::Type{Wow{K1,V1}}, ::Type{Wow{K2,V2}})
> =
> >>>     Wow{promote_type(K1,K2),promote_type(V1,V2)}
> >>>
> >>>
> >>> After that [a, b] constructs an Array{Wow{Int64,Float64},1} instead of
> an
> >>> Array{Wow,1}. The conversion method is a bit odd here since Wow
> doesn't have
> >>> any fields, but you would do the appropriate conversions if there were
> >>> fields. If there's some appropriate way to pick a common type between
> Wow
> >>> and Foo objects, that can also have promote_rules.
> >>>
> >>>
> >>> On Wed, Apr 1, 2015 at 11:02 AM, Michael Francis <[email protected]>
> >>> wrote:
> >>>>
> >>>> If I run the following, I get the results show to the right (in
> >>>> comments), it appears array construction fails to raise to the common
> >>>> parent type under certain conditions, is there a way round this?
> >>>> Alternatively where is this code implemented ?
> >>>>
> >>>> abstract Foo{K}
> >>>> type Wow{K,V} <: Foo{K} end
> >>>> type Bar{K,V} <: Foo{K} end
> >>>>
> >>>> a = Wow{Int64, Int64}()
> >>>> b = Wow{Int64, Float64}()
> >>>> c = Bar{Int64, Int64}()
> >>>> d = Bar{Int64, String}()
> >>>>
> >>>> println( "******" )
> >>>> println( typeof( [ a ]))          #Array{Wow{Int64,Int64},1}
> >>>> println( typeof( [ a, b ]))       #Array{Wow{K,V},1}
> >>>> println( typeof( [ a, c ]))       #Array{Foo{Int64},1}
> >>>> println( typeof( [ a, b, c ]))    #Array{Foo{Int64},1}
> >>>> println( typeof( [ a, c, b ]))    #Array{Foo{Int64},1}
> >>>> println( typeof( [ a, b, c, d ])) #Array{Foo{K},1}
> >>>
> >>>
> >
>

Reply via email to