putting the transpose inside, might look nicer to some:
esol = vcat([exact(t)' for t in linspace(0, 10, 100)]...)
On Tuesday, October 27, 2015 at 6:52:21 PM UTC+2, Gabriel Gellner wrote:
>
> Sadly that wants to make a matrix of two long rows ;) like the hcat(...).
> So needs the transpose as well ... maybe this is the way?
> Thanks for opening my eyes to mapreduce though!
>
> On Tuesday, 27 October 2015 09:43:59 UTC-7, Glen O wrote:
>>
>> One relatively neat way to do this is
>>
>> mapreduce(exact,hcat,linspace(0,10,100))
>>
>> On Wednesday, 28 October 2015 02:38:56 UTC+10, Gabriel Gellner wrote:
>>>
>>> Okay sorry tab seems to send ...
>>>
>>> I am trying my to figure out the Julian way to create a table of values
>>> (matrix) from a function that returns multiple values. As this is really
>>> thinking about the problem as a function that generates the rows of the
>>> table it feels super awkward to do this in Julia currently. For example,
>>> lets say I have a function of the form:
>>>
>>> function exact(t)
>>> yout = zeros(2)
>>> yout[1] = 3.0*exp(t) - 2.0*exp(t)
>>> yout[2] = exp(t) + 2.0*exp(t)
>>> yout
>>> end
>>>
>>> then what i want is a matrix of these solutions so my first thought is
>>> to do
>>>
>>> esol = [exact(t) for t in linspace(0, 10, 100)]
>>> hcat(esol...)'
>>>
>>> is this the idiomatic solution?
>>>
>>> Is there a better way to do this? How do people generally deal with
>>> Array or Arrays. Feels weird to me currently.
>>>
>>> Gabriel
>>>
>>>
>>> On Tuesday, 27 October 2015 09:31:22 UTC-7, Gabriel Gellner wrote:
>>>>
>>>> I am trying my to figure out the Julian way to create a table of values
>>>> (matrix) from a function that returns multiple values. As this is really
>>>> thinking about the problem as a function that generates the rows of the
>>>> table it feels super awkward to do this in Julia currently. For example,
>>>> lets say I have a function of the form:
>>>>
>>>> function exact_solution(t)
>>>>
>>>>
