The idea that comes to my mind is the following :
add a new variable to MyNode type wich is index,
type MyNode{T}
data::Vector{T}
level::Int
child :: Vector{MyNode}
nchild :: Int
index :: Int
end
function node_info(node)
println("Level : ", node.level)
println("nChildren: ", node.nchild)
println("data : ", node.data)
println("index ", node.index)
end
# set an empty list to store the leafs of each child
for i in 1:nChildren
list_leafs_of_child[i]= Int64[] # for instance list_leafs_of_child[1] =
[2, 5,4,9 ..]
end
for i in 1:nChildren
for j in 1:nGrandChildren
if contains(grand_children_list[i], j) # check whether j is contained in
grand_children_list[i] if so add j to the list of leafs of child[i]
# contains is a function in julia
list_leafs_of_child[i]= [list_leafs_of_child j] # add j to the list
, j : new element , list_leafs_of_child : the ancient list
end
end
but it's not working my function is not well my loop is not well defined.
sorry for these stupid questions. l'm a dummy in julia hope that l don't
bother you
On Monday, July 4, 2016 at 2:09:25 PM UTC+2, Andre Bieler wrote:
>
> Well for 1) this is pretty much exactly what is being done in my example
> code.
> The difference is that it prints out the content of "data". (But I put the
> index of
> each child into that "data" varialbe)
>
> My suggestion is that you insert a new field in the MyNode type, this
> variable
> can then hold an index. E. g. for child1 this index is 1, etc.
>
> Then do the same thing my example does in the end, but print out this
> index instead
> of data.
> I think you should try implementing this on you own, it will probably help
> you understand
> what is going on in the code. If you have problems doing so you can come
> back with more
> questions.
>
> Cheers,
> Andre
>
