For your second question, I would have expected just doing
deepcopy(MyType_Vec[[1,3,1]]) would have created a new array with a new
object allocated for each element. Instead, it puts the same object (which
is a copy) in the first and third positions and you get the same behavior.
Maybe this is not the intended behavior of deepcopy?
You can easily get around though this by explicitly calling deepcopy on
each element directly: MyType_Vec = map(deepcopy, MyType_Vec[[1,3,1]]). A
similar alternative with an array comprehension would be: MyType_Vec =
[deepcopy(MyType_Vec[i]) for i in [1,3,1]].
(an array comprehension also answers your first question: MyType_Vec =
[MyType([0.0]) for i=1:3])
On Friday, August 12, 2016 at 11:47:39 AM UTC-4, Jan wrote:
I have a beginner question for which I cannot find the answer after quite
> some searching.
>
>
> type MyType
> a::Array{Float64,1}
> end
>
> # Fill an array with "independent" instances of MyType. (By the way, is
> there a shorter way to do this?)
>
> MyType_Vec = Array(MyType, 3);
>
> for i in eachindex(MyType_Vec)
>
> MyType_Vec[i] = MyType([0.0]);
>
> end
>
> MyType_Vec
>
> # Change the value of MyType_Vec[1].a[1] to 2.
>
> MyType_Vec[1].a[1] = 2;
>
> MyType_Vec
>
> # Shuffle the vector but with repeated elements
>
> MyType_Vec = MyType_Vec[[1,3,1]];
>
> # Change the value of MyType_Vec[1].a[1] to 4.
>
> MyType_Vec[1].a[1] = 4;
>
> MyType_Vec
>
> # The value of MyType_Vec[3].a[1] also changed to 4.
>
>
> How can I avoid this reference behaviour? I want that, after the shuffling
> step, the 3 elements of MyType_Vec should be "independent" so that if I
> change MyType_Vec[1].a[1] nothing else is affected. I have tried copy and
> deepcopy without success.
>
> I would be very happy if someone could help me out. I'm stuck...
>
> Many thanks in advance.
>
