It seems that the way Julia handles A[1,:] changed in v0.5. *julia> **A = [1 2 3; 4 5 6]*
*2×3 Array{Int64,2}:* * 1 2 3* * 4 5 6* *julia> **A[1,:]* *3-element Array{Int64,1}:* * 1* * 2* * 3* *julia> **size(A[1,:])* *(3,)* A[1,:] used to be a row-vector in v0.4 same as in MATLAB, but it is now a column vector. What is the *best and most reasonable* way to retrieve rows of a matrix as a row vector? Just transpose it like A[1,:]' ?