Xavier, you could start a kernel and connect to it, instead of starting
a jupyter console. If you're using ipykernel, that just requires running
ipython kernel
Cheers,
Carlos
El 07/12/17 a las 14:57, Thomas Kluyver escribió:
Why do you want to start a console in the background? A console is an
interactive user interface, so it doesn't really make sense to run it
in the background. We can probably figure out a way to do it, but
there may be a better way to achieve what you want to do.
On 7 December 2017 at 18:23, Xavier Orduña <[email protected]
<mailto:[email protected]>> wrote:
HI!
I am trying to run jupyter console using docker and connect to
this running console from another client. If I start the container
using interactive mode (-ti) and then start the jupyter console,
everything is fine.
But if i run jupyter console as the entry point, then I got this
exception:
|
Traceback(most recent call last):
File"/usr/local/bin/jupyter-console",line 11,in<module>
sys.exit(main())
File"/usr/local/lib/python3.5/dist-packages/jupyter_core/application.py",line
266,inlaunch_instance
returnsuper(JupyterApp,cls).launch_instance(argv=argv,**kwargs)
File"/usr/local/lib/python3.5/dist-packages/traitlets/config/application.py",line
657,inlaunch_instance
app.initialize(argv)
File"<decorator-gen-116>",line 2,ininitialize
File"/usr/local/lib/python3.5/dist-packages/traitlets/config/application.py",line
87,incatch_config_error
returnmethod(app,*args,**kwargs)
File"/usr/local/lib/python3.5/dist-packages/jupyter_console/app.py",line
141,ininitialize
self.init_shell()
File"/usr/local/lib/python3.5/dist-packages/jupyter_console/app.py",line
114,ininit_shell
client=self.kernel_client,
File"/usr/local/lib/python3.5/dist-packages/traitlets/config/configurable.py",line
412,ininstance
inst =cls(*args,**kwargs)
File"/usr/local/lib/python3.5/dist-packages/jupyter_console/ptshell.py",line
273,in__init__
self.init_prompt_toolkit_cli()
File"/usr/local/lib/python3.5/dist-packages/jupyter_console/ptshell.py",line
435,ininit_prompt_toolkit_cli
output=create_output(true_color=self.true_color),
File"/usr/local/lib/python3.5/dist-packages/prompt_toolkit/shortcuts.py",line
126,increate_output
ansi_colors_only=ansi_colors_only,term=term)
File"/usr/local/lib/python3.5/dist-packages/prompt_toolkit/terminal/vt100_output.py",line
424,infrom_pty
assertstdout.isatty()
AssertionErrorIntroduïu el codi aquí...
|
As far as I understand, the error is caused when the jupyter
console tries to start the interactive terminal ...
Is there any way to launch the console in the background? without
showing the console it self in the terminal.
I checked the options and I am unable to find any of the that
suits my needs.
This is the script that starts the kernel:
|
./push_to_server.sh &
IP=`ifconfig eth0 2>/dev/null|awk '/inet addr:/ {print $2}'|sed
's/addr://'`
#ipython kernel --control=42005 --shell=42001 --iopub=42002
--hb=42003 --stdin=42004 --ip="$IP" -f /kernel_config.json
#ipython kernel --ip="$IP" -f /kernel_config.json --log-level=DEBUG
nohup jupyter console --ip="$IP"-f /kernel_config.json
--log-level=DEBUG --kernel=python3 $*
|
As you can see, i used directly ipython kernel before, but then to
have more than one kernel was complicated.
Thank you very much!
Xavi
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