Hi Thomas and Carlos,

Thanks for your ansers, let me clarify a little bit what I am trying to
achieve here.

I have a process that needs to run jupyter notebooks (using different
kernels, python2, python3, R, etc ...) but since I don't trust those
notebooks I want to execute them in a protected environment. I managed to
get this working running ipython kernel in the docker container. The
process uses a KernelClient to run the notebooks remotely in the container.

This is ok for just one environment, but if want to have many different
kernels and languages, I wanted to get advantage of wrapping them using
jupyter console. Mainly because when properly installed, jupyter console
manages kernel using the --kernel argument which makes the solution pretty
clean. This way, in case I want to add new kernels, I just need to
configure them in the docker container and launch jupyter console with a
different argument.

I know I can run ipython direclty, but it is not clear how to run other
kernels directly (for example R).

Thanks a lot!

Xavi


Xavi

-----------------------------
http://www.alcim.net

On Thu, Dec 7, 2017 at 9:09 PM, Carlos Córdoba <[email protected]> wrote:

> Xavier, you could start a kernel and connect to it, instead of starting a
> jupyter console. If you're using ipykernel, that just requires running
>
>     ipython kernel
>
>
> Cheers,
> Carlos
>
> El 07/12/17 a las 14:57, Thomas Kluyver escribió:
>
> Why do you want to start a console in the background? A console is an
> interactive user interface, so it doesn't really make sense to run it in
> the background. We can probably figure out a way to do it, but there may be
> a better way to achieve what you want to do.
>
> On 7 December 2017 at 18:23, Xavier Orduña <[email protected]>
> wrote:
>
>> HI!
>>
>> I am trying to run jupyter console using docker and connect to this
>> running console from another client. If I start the container using
>> interactive mode (-ti) and then start the jupyter console, everything is
>> fine.
>>
>> But if i run jupyter console as the entry point, then I got this
>> exception:
>>
>> Traceback (most recent call last):
>>   File "/usr/local/bin/jupyter-console", line 11, in <module>
>>     sys.exit(main())
>>   File "/usr/local/lib/python3.5/dist-packages/jupyter_core/applica
>> tion.py", line 266, in launch_instance
>>     return super(JupyterApp, cls).launch_instance(argv=argv, **kwargs)
>>   File "/usr/local/lib/python3.5/dist-packages/traitlets/config/
>> application.py", line 657, in launch_instance
>>     app.initialize(argv)
>>   File "<decorator-gen-116>", line 2, in initialize
>>   File "/usr/local/lib/python3.5/dist-packages/traitlets/config/
>> application.py", line 87, in catch_config_error
>>     return method(app, *args, **kwargs)
>>   File "/usr/local/lib/python3.5/dist-packages/jupyter_console/app.py",
>> line 141, in initialize
>>     self.init_shell()
>>   File "/usr/local/lib/python3.5/dist-packages/jupyter_console/app.py",
>> line 114, in init_shell
>>     client=self.kernel_client,
>>   File "/usr/local/lib/python3.5/dist-packages/traitlets/config/
>> configurable.py", line 412, in instance
>>     inst = cls(*args, **kwargs)
>>   File "/usr/local/lib/python3.5/dist-packages/jupyter_console/ptsh
>> ell.py", line 273, in __init__
>>     self.init_prompt_toolkit_cli()
>>   File "/usr/local/lib/python3.5/dist-packages/jupyter_console/ptsh
>> ell.py", line 435, in init_prompt_toolkit_cli
>>     output=create_output(true_color=self.true_color),
>>   File "/usr/local/lib/python3.5/dist-packages/prompt_toolkit/short
>> cuts.py", line 126, in create_output
>>     ansi_colors_only=ansi_colors_only, term=term)
>>   File "/usr/local/lib/python3.5/dist-packages/prompt_toolkit/termi
>> nal/vt100_output.py", line 424, in from_pty
>>     assert stdout.isatty()
>> AssertionErrorIntroduïu el codi aquí...
>>
>> As far as I understand, the error is caused when the jupyter console
>> tries to start the interactive terminal ...
>>
>> Is there any way to launch the console in the background? without showing
>> the console it self in the terminal.
>>
>> I checked the options and I am unable to find any of the that suits my
>> needs.
>>
>> This is the script that starts the kernel:
>>
>> ./push_to_server.sh &
>> IP=`ifconfig eth0 2>/dev/null|awk '/inet addr:/ {print $2}'|sed
>> 's/addr://'`
>> #ipython kernel  --control=42005 --shell=42001 --iopub=42002 --hb=42003
>> --stdin=42004 --ip="$IP" -f /kernel_config.json
>> #ipython kernel  --ip="$IP" -f /kernel_config.json --log-level=DEBUG
>> nohup jupyter console  --ip="$IP" -f /kernel_config.json --log-level=DEBUG
>> --kernel=python3 $*
>>
>> As you can see, i used directly ipython kernel before, but then to have
>> more than one kernel was complicated.
>>
>> Thank you very much!
>>
>> Xavi
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