> > Yes, that is correct. The equation that you quoted is indeed the probability > current

Thank you. Then to calculate the velocity, should I just divide the probability current by the integral of |𝜓|2 over the unit cell? On Mon, Jan 23, 2017 at 10:00 AM, Anton Akhmerov < anton.akhmerov...@gmail.com> wrote: > > Sorry I made a mistake in the units of 'I'. Isn't 'I' here the > probability current and not the charge current? We would just have to > multiply 'I' by e to get the charge current, right? > > Yes, that is correct. The equation that you quoted is indeed the > probability current. >