HI Jorge

Am 03.11.2014 um 21:50 schrieb cpu memhd:
> Hey Erich,
> 
> Your expand path properly handles the './', and also, another thing I 
> discovered is that with my modified expandpath, it will not always get rid of 
> redundant slashes:
> 
> my modified expandpath():
> 
> //foo/bar = /foo/bar
> 
> but then:
> 
> /foo = //foo
> 
> !?
> 
> Your expandpath seems to do what it's supposed to, but the only exception is 
> that it doesn't retain the slash when $1 is just a slash:
> 
> `expandpath2 /` = ""
> 
> 
> Nothing. But you're also saying that my expandpath does that too? I haven't 
> been able to replicate that.
> 
> Anyhow, if you can keep the slash when just '/' is passed, then that's all 
> that's needed.

That is pretty easy

either

expandpath () {
        case $1 in
                /*)     echo $1 | sed 's!//*!/!g' ;;
                *)      echo `pwd`/`echo $1 | sed 's!//*!/!g; s!^\./*!!g'`;;
        esac
       }

which always retains a trailing slash

or

expandpath () {
        case $1 in
                /)      echo $1 | sed 's!//*!/!g' ;;
                /*)     echo $1 | sed 's!//*!/!g; s!/$!!' ;;
                *)      echo `pwd`/`echo $1 | sed 's!//*!/!g;
s!^\./*!!g'` | sed 's!/$!!' ;;
        esac
       }

which only retains it in the case of a single slash.

cheers

Erich



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