You may even improve power efficiency using PSU with APFC and with lower 
max power (= lower standby losses in transformers) :)

On 28.11.2016 03:35, jean-roch blais wrote:
> Hello again List, I just revised my calculations for the power, it turns
> out assuming the current pulse is square add too much error, I integrated
> the pulse manually on the scope using 18 samples separated by 0.1 mSec,
> adding all that and spreading it over 8 mSec (= 1/60 cycles / 2 ), the
> current pulse becomes equivalent to 460 ma. So the power consumed is now =
> 55.3 watts. This is slightly better than the previous figure of 81 watts.
> At 7ยข a kwatt-hours this gives 34 canadian $. Ok I won't bug you'all with
> that any longer...
> jrb.
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