On Sep 4, 3:18 pm, "Edward K. Ream" <[email protected]> wrote:
> On Sep 4, 3:09 pm, Terry Brown <[email protected]> wrote:
>
> > w/o xpath, it's somehow search for the element with @id='co_text_holder',
> > and then somehow find its parent.
>
> How about this? ::
That computes parents. The first step in associating ids with
elements is::
def getId(e):
return id(e)
ids = {}
def computeIds(d,e):
i = getId(e)
if i: d[i] = e
for child in e.getchildren():
computeIds(d,child)
for key in ids.keys():
val = ids.get(key)
print('id: %9s element: %9s' % (key,val))
Of course, getId is wrong. But its fine for prototyping. So we're
close.
So now, given an element e, we need only find it's id attribute. But
that is easy:
def getId(e):
return e.attrib.get('id')
To test, we do:
names = (
"co_bc_1", # 1 digit black circle
"co_bc_2", # 2 digit black circle
"co_bc_text_1", # text holder for 1 digit black circle
"co_bc_text_2", # text holder for 2 digit black circle
"co_frame", # frame for speech balloon callout
"co_g_bc_1", # group for 1 digit black circle
"co_g_bc_2", # group for 2 digit black circle
"co_g_co", # group for speech balloon callout
"co_shot", # image for screen shot
"co_text_holder", # text holder for speech balloon callout
)
for name in names:
print(name,ids.get(name))
Now how hard was that?
Edward
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