Who wants to define *two *wrappers in the same decorator?
Just to be clear, this whole discussion is moot because the following works:
> @cmd('clone-find-all')
> @cmd('find-clone-all')
> And a good thing too, because I seen *no way* to define *two *wrappers in
> the same decorator. And even if there is a way, I don't particularly want
> to know about it ;-)
Are you sure?
The following solution gives you everything you want without functools and
inner wrappers.
If works for both Python2 and Python3, and the synonyms are thrown in for
free.
commands_dict = {}
# Use as function/method decorator
def cmd(*command_names):
class Decorator:
def __init__(self, func, *args):
self.func = func
try: # Python3
self.isMethod = '.' in func.__qualname__
except AttributeError: # Python 2
self.isMethod = 'instance' in str(func)
for command_name in command_names:
commands_dict[command_name] = self.__call__
def __call__(self, *args, **kwargs):
if self.isMethod:
return self.func(args[0], *args, **kwargs)
else:
return self.func(*args, **kwargs)
return Decorator
@cmd('command-first', 'first-command')
def pureFunction(event=None):
"""pureFunction docstring"""
print("-- function:", event)
class MyClass:
@cmd('command-second', 'second-command', 'another-second-command')
def instanceMethod(self, event=None):
"""instanceMethod docstring"""
print("** method:", event)
def tests():
"""Calling functions/methods from the command_dict"""
for command in commands_dict:
commands_dict[command]("I'm command <%s>." % command)
tests()
The commands are run from the dispatch dictionary (commands_dict).
Reinhard
>
>
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