On Wed, May 15, 2013 at 4:13 PM, John Peterson <[email protected]> wrote:

> On Wed, May 15, 2013 at 11:58 AM, Manav Bhatia <[email protected]>
> wrote:
> >
> >     I have attached a pdf which plots the expression for a 2-noded and a
> > 3-noded element using Lagrange interpolation functions. The element has
> unit
> > length. The 2-noded value is constant at 2 for the entire domain of the
> > element, while the 3-noded element shows a variation in the element
> domain.
> > It equals 2 at xi=0, but rises to about 8 on either end. Each quadrature
> > point uses the inverse of this function value.
>
> (I doubt stabilization is actually causing the p-convergence problems
> you're seeing, but just to clarify what I was getting at...)
>
>
> You plotted dNi/d(\xi) for these reference elements, where by "\xi" I
> mean the reference domain coordinate.
>
> But to compute the dNi/dx which is actually used in your formula, you
> have to multiply dNi/d(\xi) by the inverse jacobian, e.g.
>
> dNi/dx = dNi/d(\xi) * d(\xi)/dx
>
> For example: in 1D, a linear Lagrange element has Jacobian dx/d(\xi) =
> h/2, inverse d(\xi)/dx = 2/h, and therefore
>
> dNi/dx = (2/h) * dNi/d(\xi)
>
> which is O(1/h).
>
>
Hi John,

     It is dNi/dx that I plotted. Actually, for this 1D case, the dNi/dxi
and dNi/dx are simply scaled variants of each other by a constant (the
factor 2/h that you mentioned).

     I do follow your argument for 1/h, but varying polynomial
order also varies the tau value (reducing values of tau with higher p). How
would that reflect on identifying the h-order-dependence? Or would it stay
consistent with h^1 for tau, no matter what p is used?

Manav
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