On Fri, 2012-09-28 at 13:46 +0200, Noel Grandin wrote: > Hi > > I don't really understand the point of not being able to mutate OUString > in-place, but being able to overwrite it via the assignment operator? > > It seems to me it should be one or the other. > Either OUString is immutable, and it cannot be assigned to, except via a > constructor, or it is mutable, and we can pretty much throw away > OUStringBuffer.
Consider OUString as a smart const pointer to an immutable rtl_uString. i.e. const char *pFoo; pFoo = "hello"; pFoo = "world"; //ok pFoo[0] = 'A'; //won't compile const_cast<char*>(pFoo)[0] = 'A'; //compiles but evil C. _______________________________________________ LibreOffice mailing list [email protected] http://lists.freedesktop.org/mailman/listinfo/libreoffice
