On 28/09/12 13:46, Noel Grandin wrote: > Hi > > I don't really understand the point of not being able to mutate OUString > in-place, but being able to overwrite it via the assignment operator? > > It seems to me it should be one or the other. > Either OUString is immutable, and it cannot be assigned to, except via a > constructor, or it is mutable, and we can pretty much throw away > OUStringBuffer.
[accidentally sent this first to Noel only instead of the list] the point you are missing is that OUString is a sort of "smart pointer" to an immutable buffer. it works similarly to "String" in Java, e.g. in Java "String s = "foo"; s = "bar"" is legal but you cannot modify the content of whatever value is assigned to "s". that's why OUString has an operator= that makes it point at a different buffer but offers no way to write into the buffer (at least i hope it doesn't...). _______________________________________________ LibreOffice mailing list LibreOffice@lists.freedesktop.org http://lists.freedesktop.org/mailman/listinfo/libreoffice