Can someone point me to the place in the docs that explains libtool's handling of --mode=link when a dependent shared library is specified by full path? I'm having trouble finding it.
I'm talking about a situation like this: /bin/sh ./libtool --tag=CXX --mode=link cxx -some_compiler_flags -o libfoo.la -rpath /path/to/lib -version-info 16:3:1 -no-undefined foo.lo bar.lo baz.lo /path/to/lib/libdep.so -llib2 -lc -rpath /path/to/lib libtool should be creating libfoo.la (and both shared and archive libfoo libraries) and should be linking against /path/to/lib/libdep.so, but it's eliding the /path/to/lib/libdep.so from the shared library creation line. I'm just trying to find where this behavior is discussed, so I can understand why it's doing that. Tim -- Tim Mooney [EMAIL PROTECTED] Information Technology Services (701) 231-1076 (Voice) Room 242-J6, IACC Building (701) 231-8541 (Fax) North Dakota State University, Fargo, ND 58105-5164 _______________________________________________ http://lists.gnu.org/mailman/listinfo/libtool
