Mark Stephen Mrotek wrote
> A rather tedious, yet precise method, is:
>
> \once \set stemRightBeamCount = #x
> \once \set stemLeftBeamCount = #x
One one more thing, this method actually does not work. Think like this: the
problem isn't the number of beams for each note (these are correct) but
their overall positions.
E.g., both codes below produce identical scores:
\autochange {
\override Score.Beam.auto-knee-gap = #3
\tuplet 5/4 {g''32[e'' g''64 d a,32 gis]}
}
\autochange {
\override Score.Beam.auto-knee-gap = #3
\tuplet 5/4 {
g''32[e''
\once \set stemLeftBeamCount = #3
\once \set stemRightBeamCount = #4
g''64
\once \set stemLeftBeamCount = #4
\once \set stemRightBeamCount = #3
d a,32 gis]
}
}
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