On 14 April 2018 at 15:34, Gianmaria Lari <gianmarial...@gmail.com> wrote:
>
>
> On 14 April 2018 at 15:15, David Kastrup <d...@gnu.org> wrote:
>
>> Gianmaria Lari <gianmarial...@gmail.com> writes:
>>
>> > I don't understand the behaviour of this code:
>> >
>> > \version "2.19.81"
>> > var = {a \tag #'here {b} a}
>> > {\var} %Result: a b a
>> > {\removeWithTag #'here \var} %Result: a a
>> > {\pushToTag #'here b! \removeWithTag #'here \var} %Result: a a ;
>> Expected:
>> > a b! a
>> >
>> >
>> > The result is:
>> >
>> > a b a - ok!
>> > a a - ok!
>> > a a - not ok; shouldn't be "a b! a" ??
>>
>> \removeWithTag removes the tagged expression. Which includes the tag
>> itself.
>>
>
> This was what I was afraid of :)
>
> Any idea how I can obtain the same effect? I would like to be able to
> substitute a note in a variable with another one.
> Of course I could use "\pushToTag ... noteA" when I need noteA and
> "\pushToTag
> ... noteB" when i need noteB but I would like that my variable make sense
> also when I don't use \pushToTag command.
> Thank you, g.
>
I found a not nice solution but something that work....:
\version "2.19.81"
var = {a \tag #'herea {} \tag #'hereb {b} a}
{\pushToTag #'herea b! \removeWithTag #'hereb \var}
Ciao, g.
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