Kieren MacMillan wrote:
Hi,
it's an uncalled variable. Why should it output anything or impact anything
that's called?
1. It doesn’t output anything on its own — only when you call it. What it
impacts in that case depends on where and how you call it.
2. The input code contained in a variable sets up certain expectations
(continuations) for the parser.
Is it only durations that can leak out of uncalled variables? What else can
impact outside an uncalled variable data?
That question is better answered by people like David K, who has a far better
grasp of the internals (including the parser) than I do.
Cheers,
Kieren.
________________________________
Kieren MacMillan, composer
‣ website: www.kierenmacmillan.info
‣ email: [email protected]
I appreciate all your help Kieren. LilyPond is my favorite application.
I can't live without it. I hope I can help keep it going.
Jacques Menu Muzhic wrote:
Hello R.,
A variable is nothing more than a name for a value, a piece of text in the case
of Lily.
Using it with a backslash ahead of its name leads to this value being inserted at this point in the Lily code.
It’s the same as in all programming languages, there no implied magic at at all
behind the scenes.
The name « global » is a pure convention, which Frescobaldi chose to follow.
You could name it « blark » if you so preferred.
JM
I know but I never called it with a backslash was my point. It's
uncalled. I was trying to figure out what contents of an uncalled
variable leak out into impacting later code in the input file regardless
of it never being called ever. Thanks.
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