Hi Damian (et al.),
actually, this confuses me too
There may be a better (and, likely, more accurate) explanation than
the one I'm about to give... but this works for me, so I hope it
helps you. =)
if the # puts lilypond into scheme mode, does that mean that
the equals-sign in #'merge-differently-headed = ##t is not scheme?
Yes! You are coding a key-value setting, i.e.,
#'property-to-set = [??]
The question (and confusion) comes in how to present [??]. If
property-to-set requires [??] to be a Scheme expression -- which most
(if not all) Lilypond properties do -- then you need to tell the
parser that [??] should be interpreted as a Scheme expression:
#'property-to-set = #[??]
Now, the question remains whether [??] a "simple" number as
represented in Scheme, e.g.,
#'property-to-set = #1
or a Scheme pair, e.g.,
#'property-to-set = #'(1 . 2)
or a "reserved Scheme value", e.g.
#'property-to-set = ##t
and so on.
If property-to-set requires [??] to *not* be a Scheme expression, then
#'property-to-set = 1\mm
(or whatever) would be sufficient.
if it is, then why not #'merge-differently-headed = #t?
Because then the Scheme value of [??] would be t, which doesn't mean
anything in Scheme. ;-)
I realise this response has a roughly equal chance of making you MORE
confused as it does LESS... but I hope it's the latter!
Best wishes,
Kieren.
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