> if the # puts lilypond into scheme mode, does that mean that the
> equals-sign in #'merge-differently-headed = ##t is not scheme? if
> it is, then why not #'merge-differently-headed = #t ?
In fairness to Damian, I think his further question was more to
do with the scope of the # scheme introducer.
i.e. how much of what follows the # is interpreted
as scheme.
I'm not sure that I know the definitive answer to that
question since you can define an entire scheme function with
a single # in a different context.
In answer to his specific question about
#['merge-differently-headed = #t], it wouldn't work anyway
because the syntax of scheme is different. The assignment
here is Lilypond's syntax.
Regards,
Ralph
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