If my memory serves me correctly timeouts are actually called in reverse
order that they are in the timeout list. This makes sense in that if one
of the processes called by the timeout has the timeout forget itself then
it would be removed from the list and this would screw up the current
position in the timeoutlist as it is being processed.
You should test this to confirm but I'm pretty sure that's how it works.
Rob
On Tue, 20 Dec 2005 11:10:10 -0500, Cole Tierney <[EMAIL PROTECTED]> wrote:
At 3:27 PM +0000 12/20/05, Alan Skinner wrote:
Does director run them off a single thread or might it possibly use
multiple threads to run them?
Just a hunch, but I think timeout objects are serviced sequentially.
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