Caution when using the code below:
this will extract the first found number sequence in every file name
and use it as the property to sort the list by
If you want to sort filenames such as
image_123_342_.jpg
the algorithm will not work (or should be adapted to accomodate more
than one number sequence).
Note that the function below will skip filenames without at least one
number sequence. If you need to include them as well use:
if PRegEx_Search([aItem], "[0-9]+") > 0 then
aProp = value(PRegEx_GetMatchString())
newList.addProp(aProp,aItem)
else
newList.addProp(0,aItem)
end if
which will aggregate numberless filenames to the top of the list
have fun
Mark
On 6-jul-2006, at 17:11, Mark Hagers wrote:
If you could massage your date to get this format list:
[1: "a 1",10: "a 10",100: "a 100",11: "a 11",12: "a 12",2: "a 2",
21: "a 21"]
and then sort the resulting list, you'd get what you want.
As Sean points out, you could use PRegexXtra to extract the numeric
part from your data:
on NumSort aList
newList = [:]
newList.sort()
repeat with aItem in aList
if PRegEx_Search([aItem], "[0-9]+") > 0 then
aProp = value(PRegEx_GetMatchString())
newList.addProp(aProp,aItem)
end if
end repeat
return newList
end
put numSort(["a 1", "a 10", "a 100", "a 11", "a 12", "a 2", "a 21"])
-- [1: "a 1", 2: "a 2", 10: "a 10", 11: "a 11", 12: "a 12", 21: "a
21", 100: "a 100"]
Mark Hagers
[EMAIL PROTECTED]
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