you could do the following: pl1 = [#a:1,#b:0] pl2 = [#c:1,#d:4] pl1 = string(pl1) pl1 = char 1 to (pl1.char.count - 1) of pl1 pl2 = char 2 to pl2.char.count of pl2 newpl = value(pl1&","&pl2)
Brian Douglas (:ub) ============================================================================ [To remove yourself from this list, or to change to digest mode, go to http://www.penworks.com/lingo-l.cgi To post messages to the list, email [EMAIL PROTECTED] (Problems, email [EMAIL PROTECTED]). Lingo-L is for learning and helping with programming Lingo. Thanks!]
