At 14:39 -0500 04/10/2002, [EMAIL PROTECTED] wrote:
>so I've got 2 prop lists; I'd like to append one to the other witout
>having to do the 1 to count of the second....there's no other way, right?
And now I've got an even more condensed version.
on ConcatLists list1, list2
sList1 = string ( list1 )
delete the last char of sList1
sList2 = string (list2 )
delete char 1 of sList2
return ( value ( sList1 & "," && sList2 ) )
END ConcatLists
Let's see ActionScript do THAT! :D
--
Warren Ockrassa | http://www.nightwares.com/
Director help | Free files | Sample chapters | Freelance | Consulting
Author | Director 8.5 Shockwave Studio: A Beginner's Guide
Published by Osborne/McGraw-Hill
http://www.osborne.com/indexes/beginners_guides.shtml
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