Re: Math.ceil()...lingo style

[Daniel Nelson]

There was a discussion about this (or perhaps it was floor) on Direct-l 
last year or the year before.  Someone posted a very fast, elegant 
solution using bitXor, or something.  There are other ways as well, but 
they need a conditional to handle differences between positive and 
negative numbers.

Here are the ones I use:

on ceiling me, aNumber
  if aNumber >= 0 then return integer(aNumber + .49999999)
  --integer rounds n.5 up to n + 1, but rounds -n.5 down to -n - 1
  return integer(aNumber + .5)
end ceiling
on floor me, aNumber
  if aNumber > 0 then return integer(aNumber - .5)
  --integer rounds n.5 up to n + 1, but rounds -n.5 down to -n - 1
  return integer(aNumber - .49999999)
end floor
Regards,

Daniel

On Jan 26, 2004, at 9:10 AM, Mendelsohn, Michael wrote:

Hi all...

I want to automatically convert a float to the next highest integer.
Flash has the Math.ceil() method, so what's the most efficient way to 
do
this in Lingo?

I appreciate any responses, and have a superb day.

Thanks,
Michael M.
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