Hi guys, just joined the list. I recognise a few names here!
[From Colin Holgate]
> >if sound(1).busy = 0 then sound(1).play()
>
> This is a mixture of syntax. If you are saying sound(1).play()
> instead of puppetsound, then try using the sound(1).status instead.
How about sound(1).isBusy() ? I'm using this syntax, is it still better to
use sound(1).status?
... Alex ...
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"Accept that some days you are the pigeon and some days the statue"
Dilbert
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