>How about sound(1).isBusy() ? I'm using this syntax, is it still better to
>use sound(1).status?
I was even suspicious of that syntax! But if you say it works, I'll
believe you. The advantage of status over busy is that busy only
tells you if the sound is playing or not, whereas status can tell you
that it's not playing, but it is loading, or doing something else
that might make your logic fail.
Ok, I read up on IsBusy(), and it looks like it will work for most
cases. I'm not sure whether it would work fully if the sound channel
has queued sounds, because IsBusy() would be false, but the sound is
about to play.
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