On Friday, 01/31/2003 at 04:45 CST, "Ketchens, LeMarr T. (RyTull)" <[EMAIL PROTECTED]> wrote: > Now, all is in virtual connectivity. I have an hsi0 defined on both Linux > Guests, but I think I have it pointing to the wrong broadcast address. Can > I make up a broadcast address (10.22.25.1). or should I select the VMTCPIP > Router eth0 (10.25.25.155) or to the Cisco Router (10.25.1.1). and do change > the default of the guest to point to (10.22.25.1)?
Don't mess with the Linux broadcast address. It is selected automatically (and correctly) based on the subnet mask you provided to it. You *do* need to add a default route to the Linuxen pointing to VM TCP/IP. VM's default route is the Cisco router. You know the following information: - z/VM TCPIP on ethernet LAN => 10.25.25.155 - Linux01 on guest LAN => 10.22.25.10 - Linux02 on guest LAN => 10.22.25.11 - Cisco Router => 10.25.1.1 I extracted the following information from your PROFILE TCPIP, but I have no way of knowing if these are the values you intended (only you know the answer to that): - Subnet mask of ethernet LAN: 255.255.0.0 - Subnet mask of guest LAN: 255.255.255.0 There is one missing piece of information: - z/VM TCPIP on guest LAN I'm going to make up an address: 10.22.25.1 Given all of the above, you would code: HOME 10.25.25.155 ETH0 10.22.25.1 VHIP1 GATEWAY 10 = ETH0 1500 0.255.0.0 0.25.0.0 10 = VHIP1 1500 0.255.255.0 0.22.25.0 default 10.25.1.1 ETH0 1500 0 In each Linux, specify a default gateway of 10.22.25.1. The Cisco router will have to be told to route 10.22.25.0/24 through 10.25.25.155. Alan Altmark Sr. Software Engineer IBM z/VM Development
