On Thursday 29 May 2008 14:57, McKown, John wrote:
>I thought that I could get this from $0. But in my tests, if the script
>is on the PATH and I invoke it just with its name, I get just its name
>in return. ...
This is always a tricky problem, because various shells do it differently.
You don't seem to be running bash, because it will report the symlink's name
in $0. What I usually do is prepend the current directory to a relative
value in $0, which can be done like this in bash:
if [[ "$0" =~ /^\// ]]
then prog="$0"
else prog="$PWD/$0"
fi
Actually, I'm usually trying to write scripts that run in any sh-based shell,
so I just write: prog="$(abspath "$0")" and include an abspath() function I
wrote many years ago that uses sed to convert relative paths to absolute
paths and "normalize" them by cleaning up all "/./" and "/../" path elements.
# Convert the arguments to absolute pathnames and write them to the
# standard output
abspath()
{
for p in "$@"; do echo "$p"; done | \
sed -n -e '/^[^/]/s!\(.*\)!'$(pwd)'/\1!'\
-e ':Loop' \
-e 's!//!/!' \
-e 's!/\.$!!' \
-e 's!/[^/]\{1,\}/\.\./!/!' \
-e 's!/[^/]\{1,\}/\.\.$!!' \
-e 'tLoop' \
-e p
}
Ugly, but it works. I'm sure it can now be all done better within base using
the regular expression operator.
- MacK.
-----
Edmund R. MacKenty
Software Architect
Rocket Software, Inc.
Newton, MA USA
----------------------------------------------------------------------
For LINUX-390 subscribe / signoff / archive access instructions,
send email to [EMAIL PROTECTED] with the message: INFO LINUX-390 or visit
http://www.marist.edu/htbin/wlvindex?LINUX-390
